3[2x-1]=9[x+3]

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Solution for 3[2x-1]=9[x+3] equation:


Simplifying
3[2x + -1] = 9[x + 3]

Reorder the terms:
3[-1 + 2x] = 9[x + 3]
[-1 * 3 + 2x * 3] = 9[x + 3]
[-3 + 6x] = 9[x + 3]

Reorder the terms:
-3 + 6x = 9[3 + x]
-3 + 6x = [3 * 9 + x * 9]
-3 + 6x = [27 + 9x]

Solving
-3 + 6x = 27 + 9x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9x' to each side of the equation.
-3 + 6x + -9x = 27 + 9x + -9x

Combine like terms: 6x + -9x = -3x
-3 + -3x = 27 + 9x + -9x

Combine like terms: 9x + -9x = 0
-3 + -3x = 27 + 0
-3 + -3x = 27

Add '3' to each side of the equation.
-3 + 3 + -3x = 27 + 3

Combine like terms: -3 + 3 = 0
0 + -3x = 27 + 3
-3x = 27 + 3

Combine like terms: 27 + 3 = 30
-3x = 30

Divide each side by '-3'.
x = -10

Simplifying
x = -10

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